Pyhton İle Site İçerisindeki Bir Bölümdeki Kelimeyi Bulmak
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name=\"(.*?)\"
flavordan python seç, toolstan code generator tıkla.
# coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r"name=\"(.*?)\"" test_str = ("<td>\n\n" "<input id=\"isim\" style=\"width:240px;\" name=\"isim\" type=\"text\">\n\n" "</td>") matches = re.finditer(regex, test_str, re.MULTILINE) for matchNum, match in enumerate(matches, start=1): print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group())) for groupNum in range(0, len(match.groups())): groupNum = groupNum + 1 print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum))) # Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution. -
bunu mu demek istediniz?
//*[@id="isim" and contains(@value, "aranan deger")]
not: python, xpath, selenium, regex bilmiyorum.
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hocam, seleniul ide ile recort yap, sonra rocordu pytona çevir yapamassan özelden gel
